Integrand size = 23, antiderivative size = 33 \[ \int \cos (c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {a \sin ^2(c+d x)}{2 d}+\frac {a \sin ^3(c+d x)}{3 d} \]
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Time = 0.02 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {2912, 12, 45} \[ \int \cos (c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {a \sin ^3(c+d x)}{3 d}+\frac {a \sin ^2(c+d x)}{2 d} \]
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Rule 12
Rule 45
Rule 2912
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {x (a+x)}{a} \, dx,x,a \sin (c+d x)\right )}{a d} \\ & = \frac {\text {Subst}(\int x (a+x) \, dx,x,a \sin (c+d x))}{a^2 d} \\ & = \frac {\text {Subst}\left (\int \left (a x+x^2\right ) \, dx,x,a \sin (c+d x)\right )}{a^2 d} \\ & = \frac {a \sin ^2(c+d x)}{2 d}+\frac {a \sin ^3(c+d x)}{3 d} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.91 \[ \int \cos (c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {-3 a \cos (2 (c+d x))+4 a \sin ^3(c+d x)}{12 d} \]
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Time = 0.07 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.85
method | result | size |
derivativedivides | \(\frac {\frac {a \left (\sin ^{3}\left (d x +c \right )\right )}{3}+\frac {a \left (\sin ^{2}\left (d x +c \right )\right )}{2}}{d}\) | \(28\) |
default | \(\frac {\frac {a \left (\sin ^{3}\left (d x +c \right )\right )}{3}+\frac {a \left (\sin ^{2}\left (d x +c \right )\right )}{2}}{d}\) | \(28\) |
parallelrisch | \(-\frac {a \left (-3-3 \sin \left (d x +c \right )+\sin \left (3 d x +3 c \right )+3 \cos \left (2 d x +2 c \right )\right )}{12 d}\) | \(37\) |
risch | \(\frac {a \sin \left (d x +c \right )}{4 d}-\frac {a \sin \left (3 d x +3 c \right )}{12 d}-\frac {a \cos \left (2 d x +2 c \right )}{4 d}\) | \(44\) |
norman | \(\frac {\frac {2 a \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {2 a \left (\tan ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d}+\frac {8 a \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3 d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{3}}\) | \(69\) |
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Time = 0.34 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.18 \[ \int \cos (c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=-\frac {3 \, a \cos \left (d x + c\right )^{2} + 2 \, {\left (a \cos \left (d x + c\right )^{2} - a\right )} \sin \left (d x + c\right )}{6 \, d} \]
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Time = 0.11 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.24 \[ \int \cos (c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\begin {cases} \frac {a \sin ^{3}{\left (c + d x \right )}}{3 d} + \frac {a \sin ^{2}{\left (c + d x \right )}}{2 d} & \text {for}\: d \neq 0 \\x \left (a \sin {\left (c \right )} + a\right ) \sin {\left (c \right )} \cos {\left (c \right )} & \text {otherwise} \end {cases} \]
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Time = 0.22 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.85 \[ \int \cos (c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {2 \, a \sin \left (d x + c\right )^{3} + 3 \, a \sin \left (d x + c\right )^{2}}{6 \, d} \]
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Time = 0.31 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.85 \[ \int \cos (c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {2 \, a \sin \left (d x + c\right )^{3} + 3 \, a \sin \left (d x + c\right )^{2}}{6 \, d} \]
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Time = 0.05 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.73 \[ \int \cos (c+d x) \sin (c+d x) (a+a \sin (c+d x)) \, dx=\frac {a\,{\sin \left (c+d\,x\right )}^2\,\left (2\,\sin \left (c+d\,x\right )+3\right )}{6\,d} \]
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